-[4z-(7z+1)]=1+(2z+3)

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Solution for -[4z-(7z+1)]=1+(2z+3) equation:


Simplifying
-1[4z + -1(7z + 1)] = 1 + (2z + 3)

Reorder the terms:
-1[4z + -1(1 + 7z)] = 1 + (2z + 3)
-1[4z + (1 * -1 + 7z * -1)] = 1 + (2z + 3)
-1[4z + (-1 + -7z)] = 1 + (2z + 3)

Reorder the terms:
-1[-1 + 4z + -7z] = 1 + (2z + 3)

Combine like terms: 4z + -7z = -3z
-1[-1 + -3z] = 1 + (2z + 3)
[-1 * -1 + -3z * -1] = 1 + (2z + 3)
[1 + 3z] = 1 + (2z + 3)

Reorder the terms:
1 + 3z = 1 + (3 + 2z)

Remove parenthesis around (3 + 2z)
1 + 3z = 1 + 3 + 2z

Combine like terms: 1 + 3 = 4
1 + 3z = 4 + 2z

Solving
1 + 3z = 4 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
1 + 3z + -2z = 4 + 2z + -2z

Combine like terms: 3z + -2z = 1z
1 + 1z = 4 + 2z + -2z

Combine like terms: 2z + -2z = 0
1 + 1z = 4 + 0
1 + 1z = 4

Add '-1' to each side of the equation.
1 + -1 + 1z = 4 + -1

Combine like terms: 1 + -1 = 0
0 + 1z = 4 + -1
1z = 4 + -1

Combine like terms: 4 + -1 = 3
1z = 3

Divide each side by '1'.
z = 3

Simplifying
z = 3

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